php start.php start -d 出错,这个怎么处理?

xiaodong

问题描述

这里写描述
fopen(): Filename cannot be empty in file /www/wwwroot/webman_axb_api/vendor/workerman/workerman/Worker.php on line 1294
PHP Fatal error: Uncaught Exception: Can not open stdoutFile in /www/wwwroot/webman_axb_api/vendor/workerman/workerman/Worker.php:1325
Stack trace:

0 /www/wwwroot/webman_axb_api/vendor/workerman/workerman/Worker.php(1599): Workerman\Worker::resetStd()

1 /www/wwwroot/webman_axb_api/vendor/workerman/workerman/Worker.php(1426): Workerman\Worker::forkOneWorkerForLinux(Object(Workerman\Worker))

2 /www/wwwroot/webman_axb_api/vendor/workerman/workerman/Worker.php(1400): Workerman\Worker::forkWorkersForLinux()

3 /www/wwwroot/webman_axb_api/vendor/workerman/workerman/Worker.php(560): Workerman\Worker::forkWorkers()

4 /www/wwwroot/webman_axb_api/vendor/workerman/webman-framework/src/support/App.php(131): Workerman\Worker::runAll()

5 /www/wwwroot/webman_axb_api/start.php(4): support\App::run()

6 {main}

thrown in /www/wwwroot/webman_axb_api/vendor/workerman/workerman/Worker.php on line 1325

694 1 0
1个回答

hon陈烁临

盲猜是 config/app.php 里面的runtime_path配置有问题

年代过于久远,无法发表回答
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